I'm getting this error message:

[Cyberclops]

After I enable my SuSE 7.1 firewall configuration, I get the following
message"

>>>>Apr  9 06:17:45 a24b161n139client142 ntpdate[483]: no server suitable for synchronization found<<<<<

But if the firewall is not actuated I get this:

>>>>Apr  8 12:55:27 a24b161n139client142 ntpdate[308]: step time server 128.2.191.71 offset 0.255133 sec<<<<<

I have a time fetish and like the clock on my computer to be perfectly
synchronized to and Internet time standard.  Can anyone tell me how to
get this signal to pass through the SuSE 7.1 firewall?  Note: it uses
the 2.4 kernel.

With the firewall activated I'm reported as "totally stealth" at the
"Shields Up" web site.  That's something I like:  Here is the log
entries from the "Shields Up" probe:

Apr  9 06:24:28 a24b161n139client142 kernel: Packet log: output DENY
eth0 PROTO=1 24.161.139.142:3 24.25.227.34:3 L=203 S=0xC0 I=0 F=0x4000
T=255 (#3)
Apr  9 06:24:35 a24b161n139client142 kernel: Packet log: output DENY
eth0 PROTO=1 24.161.139.142:3 24.25.227.34:3 L=442 S=0xC0 I=0 F=0x4000
T=255 (#3)
Apr  9 06:30:50 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4022 24.161.139.142:21 L=48 S=0x00 I=52344
F=0x4000 T=113 SYN (#12)
Apr  9 06:30:53 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4022 24.161.139.142:21 L=48 S=0x00 I=53116
F=0x4000 T=113 SYN (#12)
Apr  9 06:31:00 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4022 24.161.139.142:21 L=48 S=0x00 I=54885
F=0x4000 T=113 SYN (#12)
Apr  9 06:31:13 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4108 24.161.139.142:23 L=48 S=0x00 I=58353
F=0x4000 T=113 SYN (#16)
Apr  9 06:31:16 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4108 24.161.139.142:23 L=48 S=0x00 I=59358
F=0x4000 T=113 SYN (#16)
Apr  9 06:31:23 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4108 24.161.139.142:23 L=48 S=0x00 I=60730
F=0x4000 T=113 SYN (#16)
Apr  9 06:31:59 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4267 24.161.139.142:79 L=48 S=0x00 I=3289 F=0x4000
T=113 SYN (#20)
Apr  9 06:32:02 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4267 24.161.139.142:79 L=48 S=0x00 I=4139 F=0x4000
T=113 SYN (#20)
Apr  9 06:32:09 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4267 24.161.139.142:79 L=48 S=0x00 I=5581 F=0x4000
T=113 SYN (#20)
Apr  9 06:32:45 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4382 24.161.139.142:110 L=48 S=0x00 I=13162
F=0x4000 T=113 SYN (#22)
Apr  9 06:32:48 a24b161n139client142 kernel: Packet log: input DENY eth0
PROTO=6 207.71.92.221:4382 24.161.139.142:110 L=48 S=0x00 I=13806
F=0x4000 T=113 SYN (#22)